Submission #7465275

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Source Code Expand

#!/usr/bin/env python3

N = int(input().split()[0])
a_list = list(map(int, input().split()))

num2group_dict = {}
group_dict = {}
group_id = 0

for i, a in enumerate(a_list):
    if i not in group_dict:
        if a in num2group_dict:
            group_dict[i] = num2group_dict[a]
        else:
            group_dict[i] = group_id
            num2group_dict[a] = group_id
    x2_list = [(j, x) for j, x in enumerate(a_list) if x == 2 * a]
    if x2_list:
        for j, x in x2_list:
            # 2xの整数を同じグループにする
            group_dict[j] = group_dict[i]
            num2group_dict[x] = group_dict[i]
    group_id += 1

ans = len(list(set(list(group_dict.values()))))

print(ans)

Submission Info

Judge Result